Question: R, S and T are 3 consecutive odd integers.
Column A
|
Column B
|
R + S + 1
|
S + T – 1
|
Solution: Let R = 1, then S = 3, T = 5
Column A= R + S + 1 = 1 + 3 + 1 = 5.
Column B = S + T – 1 = 3 + 5 – 1 = 7.
Column B is Greater.
But let R = -1, then S = -3, T = - 5
Column A = R + S + 1 = -1 – 3 + 1 = -3.
Column B = S + T – 1 = -3 – 5 – 1 = -9.
Now, column A is greater.
So, answer is option (D).