Antonio is 5 years older to Brenda and 7 years younger to Caflice, while Brenda and Darshan are twins. How many years older is Caflice to Darshan?
A. 10
B. 18
C. 14
D. 12
Option: D Explanation: Since Brenda and Darshan are twins, so Brenda = Darshan.
Now, Antonio = Brenda + 5 and Antonio = Caflice - 7.
Thus, Brenda + 5 = Caflice - 7 ⇔ Darshan + 5 = Caflice -7 ⇔ Caflice - Darshan = 12
The 40 veteran players decide to play a Badminton singles tournament. The condition of the tournament is that if a player loses a game he is out of the tournament and also there is no tie. Organizers have to conduct what minimum number of games in order to decide the winner?
A. 20
B. 25
C. 39
D. None of these
Option: C Explanation: Clearly, every player except one (i.e. the winner) must lose one game to decide the winner. Thus, the minimum number of matches to be played = 40 - 1 = 39.
We have 16 columns and 18 rows of students in a playground and distance between the two students is 1.5metres. The length of the row of students is
A. 20.5 m
B. 22.5 m
C. 22 m
D. 25.5 m
Option: D Explanation: Each row contains 18 students.
There are 17 gaps between the two students (17 x 1.5) metres = 25.5m.
Therefore length of the row = 25.5m.
Mukesh is 40 years old and he is five times as old as his brother Rohit. When Mukesh is thrice as old as Rohit then age of Mukesh is
A. 44 years
B. 46 years
C. 48 years
D. 40 years
Option: C Explanation: Mukesh's present age = 40 years, Rohit's present age = 8 years.
Let Mukesh be thrice as old as Rohit after x years from now.
Then, 40 + x = 3 (8 + x). So, 40 + x = 24 + 3x. Hence, x = 8.
Hence, Mukesh's required age = 40 + x = 48 years
In ASEAN Summit, all leaders shake hands with each other once. How many handshakes will there be altogether if there are 15 leaders?
A. 105
B. 85
C. 75
D. 100
Option: A Explanation: First person has 14 people for shake hands.
Second person has 13 people for shake hands and so on till the last person who doesnot have anyone left for handshake.
So,total number of handshakes =14+13+12+11+10+9+8+7+6+5+4+3+2+1 = 105
Rimpy is thrice as old as Saroj. Four years ago, she was five times as old as Saroj. How old is Rimpy now?
A. 21 years
B. 12 years
C. 24 years
D. 16 years
Option: C Explanation: Let Saroj's present age = x years
Then Rimpy present age = 3x years
Four years ago
(3x-4) = 5(x-4)
3x - 4 = 5x - 20
or x = 8
Rimpy age = 3x = 3*8= 24 years.
A zoo has tigers and sparrows and they are 70 in number on counting their heads and the number of their legs is 210. How many sparrows are there?
A. 37
B. 35
C. 55
D. 25
Option: B Explanation: Let x and y be the number of tigers and sparrows in the zoo respectively. Then,
x + y = 70 ...(i) and
4x + 2y = 210 or 2x + y = 105 ...(ii)
Solving (i) and (ii), we get) x = 35, y = 35.
A school has 2100 students. For every 20 students there is one class monitor. The number of monitors in the school is
A. 100
B. 75
C. 80
D. 85
Option: A Explanation: Generally we may commit mistake of dividing 2100/20.
But out of 21 students there is one monitor.
So, it will be 2100/21 = 100
Abdul comes across four roundabouts i.e A,B,C,D while he travels to his office from home. He knows three ways to reach roundabout B from A and five ways from B to C and four ways from C to D. In how many ways he can reach his office from home?
A. 20
B. 12
C. 15
D. 60
Option: D Explanation: Total number of ways from home to office = (3 x 5 x 4) = 60.
Two friends Manish and Kapil went to New Year party and they played several monetary games in that party. Kapil had Rs.200 less than Manish before playing games but after the party, he had made his money six times of what he had with him initially or he had Rs.400 more than what they both had with them initially. So how much money Manish had with him before playing games?
A. Rs.500
B. Rs.400
C. Rs.250
D. Rs.350
Option: D Explanation: Let money with Kapil = x. Then, money with Manish = x + 200
Now, 6x = (x + x + 200) + 400. Hence, x = 150.
Therefore, money with Manish initially = 150 + 200 = Rs.350
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