22756
Unique Id: 18773
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DIRECTIONS
for the question:
Solve the following question and mark the best possible option.
A cyclist travels a distance of 180 m in 12 seconds. How much faster in Kmph must he travel to complete such a trip in 3/4
th
of the original time?
A)
18 km/hr
B)
36 km/hr
C)
72 km/hr
D)
None of these
A
Original speed of the cyclist = 180/12 = 15m/s = 15×18/5 = 54 kmph
3/4
th
of the original time = 12×3/4 = 9 seconds
Thus, new speed of the cyclist = 180/9 = 20m/s = 20×18/5 = 72 kmph
Extra speed = 72 – 54 = 18kmph
Question include in Following Tests :
TSD Level I - 02
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CUET - TSD - PE 04
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CUET PG - Time Speed & Distance - PE 04
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