113552
Unique Id: 102969
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DIRECTIONS
for the question:
Solve the following question and mark the best possible option.
The sum of two three-digit number b67 and aa5 is a four-digit number 1a12. What is the value of (a + b)?
A)
10
B)
11
C)
12
D)
13
E)
14
D
b67
+aa5
1a12
7+5 = 12;
6+a+1 = 1 unit digit, which means a = 4
1+4+b = 4 unit digit, which means b = 9
Therefore a+b = 13
Question include in Following Tests :
PDF CAPQ - Number & Average 04
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WIN IBSAT 06 (2024)
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