DIRECTIONS for the question:Solve the following question and mark the best possible option.
A committee is to be formed from amongst 9 boys and 6 girls. In how many ways can the boys and girls divide themselves into groups of three so that no group has more than 2 girls and no group has all boys?
A)
B)
C)
15*9!
D)
(​15/16)*9!
E)
(​15/16)*8!
D
1 group will have 2g and 1b
4 groups will have 1 g and 2b
2g 1b can be selected in 6c2 * 9c1 ways
For 1g and 2b
4 girls will always be divided automatically
4 boys are selected as, 8c2*6c2*4c2*2c2 = 8!/24
Overall answer = 15*9*8!/24
(15/16)*9!
