113453
Unique Id: 102944
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DIRECTIONS
for the question:
Solve the following question and mark the best possible option.
If a, b, c, d and e are five consecutive odd numbers, then (a
2
+ b
2
+ c
2
+ d
2
+ e
2
) is always divisible by
A)
2
B)
3
C)
4
D)
5
E)
6
D
Let a,b,c,d,e, br 1,3,5,7,9
Sum of thei squares is 1+9+25+49+81 = 165
It is divisible by 5.
Hence 5 is the answer.
Question include in Following Tests :
WIN IBSAT 06 (2024)
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