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Square Root & Cube Root Practice Problems: Level 02

Learn to solve the tricky questions based on square and cube roots. The answer key and explanations are given for the practice questions.
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Q1. What is the cube root of 2197?
A. 12
B. 13
C. 14
D. 15
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Sol : Option B
Explanation factorization of 2197: 13 * 13 * 13. Therefore, cube root of 2197 is 13.
Q2. What approximate value will come (?) in the following equation?
17.32% of 190 - 3&redic;26.881 = ?
A. 12
B. 50
C. 29
D. 80
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Sol : Option C
Explanation: We have 17.32% of 190 - 3&redic;26.881 = ?
⇒ 17% of 190 - 3&redic;
⇒ ? = (20% - 3%) of 190 – 3= 38 – 5.7 – 3 = 29.3. Hence the answer is Option C
Q3. The cube root of 0.000216 is:
A. 0.6
B. 0.06
C. 0.77
D. 0.87
Sol : Option B
Explanation: (0.000216)1/3 = (0.06 × 0.06 × 0.06)1/3 = [(0.06)3]1/3 = 0.06
Q4. Find the least number by which 750 should be multiplied, so that it becomes a perfect cube.
A. 12
B. 24
C. 36
D. 48
Sol : Option C
Explanation: Prime factorization of 750= (2 * 3 * 5 * 5 * 5)
To make it perfect cube we should multiply with (2 * 2) * (3 * 3) = 36.
5. The value of &redic;0.64 + &redic;1.44 + &redic;0.0009 is:
A. 2.03
B. 2.1
C. 2.11
D. 2.13
Sol : Option A
Explanation: Given exp. = &redic;64/100 + &redic;144/100 + &redic;9/10000 = 8/10 + 12/10 + 3/100
= 0.8 + 1.2 + 0.03 = 2.03
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Q.6. Which is the smallest number, with which 600 should be multiplied so that it becomes a perfect square?
A. 2
B. 3
C. 3.5
D. 6
Sol : Option D
Explanation: 600= 5 * 5 * 3 * 2 * 2 * 2, to make it perfect square it should be multiplied by 3 * 2 = 6.
Q.7. In a class each of the students contributed as many paisa as there are number of students. If the total collection was Rs. 169, what was the number of students in the class?
A. 113
B. 112
C. 130
D. 120
Sol : Option C
Explanation: Let number of students be y. They all contributed y paisa each.
So, y * y = 16900 paisa. Hence y = 130.
Q8. A person wants to arrange his colleagues in the form of a perfect square, but he finds there are 9 persons too many. What will be the total number of persons in front row, if the total number of persons with him is 2410?
A. 41
B. 47
C. 48
D. 49
Sol : Option D
Explanation: Let persons in the first row be y,
So, (y × y) + 9 = 2410. Solving this, we get the value of y as 49.
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Q9. If &redic;15625 = 125, then the value of (&redic;156.25 + &redic;1.5625 + &redic;0.015625 + &redic;0.00015625) is
A. 1.38875
B. 13.8875
C. 138.875
D. 1388.75
Sol : Option B
Explanation: [image] = 12.5 + 1.25 + 0.125 + 0.0125 = 13.8875
Q10. An army man wants to arrange his men in the form of a perfect square, but he finds there are 64 men too many. What will be the total number of men in front row, if the total number of men with him is 15440?
A. 121
B. 134
C. 124
D. 13
Sol : Option C
Explanation: Required number of men in the front row = &redic;15440-64 = &redic;15376 = 124
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