Rectangle: In a rectangle, opposite sides are parallel and congruent.
Area = length * breadth
Diagonal of the rectangle = √(l2 + b2)
Area = length * breadth
Perimeter = 2 (length + breadth)
Square: All sides and angles of a square are congruent.
Length of the diagonal = l √2 (where l is the length of the side of a square)
Area = (Side)2
Perimeter = 4 X side
Rhombus: All sides and all opposite angles of a rhombus are congruent. Also, the diagonals are perpendicular to and each other.
Area = (a*b)/2 (where a and b are the lengths of the diagonals of a rhombus)
Perimeter = 4 * length
Trapezium: No sides, angles and diagonals of a trapezium are parallel to each other.
Area = (1/2)h*(L+L2)
Perimeter = L + L1 + L2 + L3
Important Points
Of all the quadrilaterals of the same perimeter, the one with the maximum area is the square.
The quadrilateral formed by joining the midpoints of the sides of any quadrilateral is always a parallelogram (rhombus in case of a rectangle, rectangle in case of a rhombus and square in case of a square).
The quadrilateral formed by the angle bisectors of the angles of a parallelogram is a rectangle.
For a rhombus □ABCD, if the diagonals are AC and BD, then AC2 + BD2 = 4 * AB2.
If a square is formed by joining the midpoints of a square, then the side of the smaller square = side of the bigger square/√2.
If P is a point inside a rectangle □ABCD, then AP2 + CP2 = BP2 + DP2.
The segment joining the midpoints of the non-parallel sides of a trapezium is parallel to the two parallel sides and is half the sum of the parallel sides.
For a trapezium □ABCD, if the diagonals are AC and BD, and AB and CD are the parallel sides, then AC2 + BD2 = AD2 + BC2 + 2 * AB * BD.
If the length of the sides of a cyclic quadrilaterals area, b, c and d, then it's area = √(s-a)(s-b)(s-c)(s-d) , where s is the semi - perimeter.
The opposite angles of a cyclic quadrilateral are supplementary.