Sol: Option 1 Explanation: Total no. of Digits = 12. Equally likely cases = 12.
There are six odd digits. Probability = 6 / 12 = 1 / 2
Determine the probability that a digit chosen at random from digits 1, 2, 3, ….. 13 will be even.
1. 1/2
2. 1/9
3. 5/9
4. 6/13
Sol: Option 4 Explanation: Here out of six digits (2, 4, 6, 8,10, 12), any digits chosen will be considered favorable. Probability = 6 / 13
A coin is tossed four times, if H = head and T = tail, what is the probability of the tosses coming up in the order HTHH?
1. 3/16
2. 1/16
3. 5/16
4. 7/16
Sol: Option 2 Explanation: Coin is tossed four times. The total possible outcomes = 16.
Favorable outcomes = 1.Because HTHH can come only in one way, Probability = 1 / 16
A dice is thrown, what is the probability that the number obtained is a prime number.
1. 1/6
2. 1/8
3. 1/2
4. 1/3
Sol: Option 3 Explanation: Dice is thrown, the total possible outcomes = 6.
Favorable outcomes = 3 i.e. (2,3,5). Probability = 3 / 6 = 1 / 2
Find the probability of throwing a total of 8 in a single throw with two dice.
1. 1/36
2. 5/36
3. 25/36
4. 12/36
Sol: Option 2 Explanation: Two Dice are thrown, the total possible outcomes = 36.
Favorable outcomes = 5 i.e. (2, 6), (6, 2), (3, 5), (5, 3), (4, 4).
Therefore, Probability = 5 / 36
If a dice is thrown twice, what is the probability of not getting a one on either throw?
1. 1/12
2. 1/18
3. 25/36
4. 12/36
Sol: Option 3 Explanation: Out of total 36 possible outcomes, getting 1 on either draw can happen in = 11 ways
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Reqd. Probability = 1 – (Probability of Getting one on either draw) = 1 - 11 / 36 = 25 / 36
A card is drawn from a pack of 52 cards. What is the probability that the card is a Queen?
1. 1/52
2. 1/4
3. 1/16
4. None of these
Sol: Option 4 Explanation: Total possible outcomes = 52.
Favorable outcomes = 4.
Probability = 4 / 52 = 1 / 13
Two cards are drawn in succession from a pack of 52 cards, without replacement. What is the probability, that the first is a Queen and the second is a Jack of a different suit?
Sol: Option 4 Explanation: The probability of first Queen = 4 / 52
The probability of Second Jack of different suit = 3 / 51
Reqd. Probability = (4/52) x (3/51) = (1/13) x (1/17) = (1/221)
Two dice are thrown, what is the probability that both the dices are not having the same number.
1. 1/4
2. 5/6
3. 1/9
4. 1/12
Sol: Option 2 Explanation: Total possible outcomes = 36. Favorable outcomes of having same number = 6 [(1, 1) (2, 2) (3, 3) (4, 4) (5, 5) (6, 6)].
Probability of both the dices having same number = 6 / 36 = 1 / 6
Required probability = 1 - 1 / 6 = 5 / 6
Determine the probability that a number chosen at random from the digits 1, 2, 3, ……., 10 will be a multiple of 4.