Simple and Compound Interest Problems with Solutions

Before going to the simple interest and compound interest problems, you should revise the simple and compound interest formulas. After revising the formulas you will understand the following examples.
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Example 1:If the difference between Simple Interest and Compound Interest on a certain sum of money in 2 years at 20 % p.a. is Rs. 800, then find the sum.
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Sol:If difference between Simple Interest & Compound Interest for 2 years is Rs. x, then Principal = x
(100/r)2 P = 800 X 10000/20*20 → P = 20000. Hence the sum is Rs. 20000.
Example 2:The compound interest on a certain sum of money for 2 years is Rs. 52 and the simple interest for the same time at the same rate is Rs. 50. Find the rate %.
Sol:SI for 2 years = 50, CI for 2 years = 52. therefore As, SI and CI are same for the first year,
therefore, SI and CI for 1st year = Rs. 25. So CI for 2nd year = 52 – 25 = 27
i.e. a difference of Rs. 2 on 1st year’s interest of Rs. 25. Hence rate of interest = 100 X 2/25 = 8%.
Example 3:The difference between Compound Interest and Simple Interest on a certain sum of money at 10 % per annum for 3 years is Rs. 930. Find the principal if it is known that the interest is compounded annually.
Sol: The Simple Interest after three years @ 10% is 30%.
The Compound Interest after 3 years @ 10% will be 1.1 × 1.1 × 1.1 = 1.331  Cumulative rate of Interest is 33.1%.
Here, the difference after 3 years is 3.1% and in the question it is given to be Rs. 930.
Thus, the Principal is 930 × 100/3.1 = Rs. 30000.
Example 4:The population of a town has a constant growth of 4% p.a. If its present population is 62,500, what will be its population after two years?
Sol:: Population after 2 years = P (1 + 4/100)2 = 62500 X (104/100)2
= 62500 × 26/25 X 26/25 = 100 × 26 ×26 = 67600.
Hence, the population after two years will be 67,600.
Example 5:The cost of a new washing machine is Rs. 12000. Its value depreciates every year at the rate of 10%. What will be its value after three years?
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Sol:The cost of washing machine = Rs. 12000
Rate of depreciation = 10%, Time = 3 years
Due to depreciation, the price of the washing machine is reduced.
Therefore, Price of washing machine after three years
= Rs. 12000 × (1 - 10/100)3 = Rs. 12000 × (90/100)3 = Rs. 12000 × 9/10 x 9/10 x 9/10 = Rs. 8748.
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